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Calculation method for assessing
Thermal Bridging at the edges of openings
Example
The diagram below shows a window jamb in a masonry cavity wall,
with Therma-Close closing the cavity.
Robust details require a cavity closer with a minimum Thermal Resistance
of 0.45m²K/W
Calculation of Thermal
Resistance Path (‘R’ value)
This table shows the thermal
resistance for each segment
of the path ABCD. The thermal
resistance for each segment
is obtained by dividing the
length of the path segment
in metres by its thermal
conductivity in W/mK
| Path segments |
Length (m) |
Conductivity (W/mK) |
Resistance (m²K/W) |
A - B |
0.0275 |
0.12 |
0.23 |
B - C |
0.030 |
0.029 |
1.034 |
C - D |
0.040 |
0.770 |
0.052 |
Thermal Resistance Path ('R'
value) = 1.316m²K/W |
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